Exercise 13.

Let \(\phi_n(x) = x^n\) for \(0 \leq x \leq 1\) and show that
\begin{equation*} \lim_{n \rightarrow \infty} \phi_n(x) = \begin{cases} 0, & 0 \leq x \lt 1 \\ 1, & x = 1. \end{cases} \end{equation*}
This is an example of a sequence of continuous functions that does not converge to a continuous function, which helps explain the need for uniform continuity in the proof of the Existence and Uniqueness Theorem.
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